4x^(1/2)=0.2x

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Solution for 4x^(1/2)=0.2x equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

4*x^(1/2) = 0.2*x // - 0.2*x

4*x^(1/2)-(0.2*x) = 0

4*x^(1/2)-0.2*x = 0

t_1 = x^(1/2)

4*t_1^1-0.2*t_1^2 = 0

4*t_1-0.2*t_1^2 = 0

DELTA = 4^2-(-0.2*0*4)

DELTA = 16

DELTA > 0

t_1 = (16^(1/2)-4)/(-0.2*2) or t_1 = (-16^(1/2)-4)/(-0.2*2)

t_1 = 0 or t_1 = 20

t_1 = 0

x^(1/2)+0 = 0

x^(1/2) = 0

1*x^(1/2) = 0 // : 1

x^(1/2) = 0

x = 0

t_1 = 20

x^(1/2)-20 = 0

1*x^(1/2) = 20 // : 1

x^(1/2) = 20

x^(1/2) = 20 // ^ 2

x = 400

x in { 0, 400 }

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